Problem | #1 | #2 | #3 | #4 | #5 | #6 | #7 | #8 | #9 | #10 | Total |
---|---|---|---|---|---|---|---|---|---|---|---|
Max grade | 10 | 10 | 10 | 10 | 10 | 10 | 10 | 10 | 10 | 10 | 98 | Min grade | 6 | 2 | 3 | 0 | 7 | 0 | 4 | 6 | 0 | 1 | 55 | Mean grade | 9.06 | 8.5 | 8.83 | 7.76 | 9.33 | 8.50 | 8.72 | 9.39 | 7.44 | 8.06 | 85.39 | Median grade | 10 | 10 | 10 | 9 | 10 | 9.5 | 9 | 10 | 8 | 9 | 92.99 |
Numerical grades will be retained for use in computing the final
letter grade in the course.
Here are approximate letter grade assignments for this exam:
Letter equivalent | A | B+ | B | C+ | C | D | F |
---|---|---|---|---|---|---|---|
Range | [90,100] | [85,89] | [75,84] | [70,74] | [60,69] | [55,59] | [0,54] |
Grading guidelines
Minor errors (such as a missing factor in a final answer, sign error,
etc.) were penalized minimally. Students whose errors materially
simplify the problem were not be eligible for most of the
problem's credit.
The grader will read only what is written and not attempt to guess or
read the mind of the student.
The student should solve the problem given and should not invent
another problem and request credit for working on that problem.
Problem 1 (10 points)
4 points for the graph (three points in correct positions at the
vertices of an equilateral triangle), and 2 points for each of the
roots, a total of 6 points. 3 points partial credit are earned if some
correct algebraic work is shown. Only 3 of 6 points for the roots are
earned if specific values of sine and cosine are not given.
Problem 2 (10 points)
3 points for correctly setting up a verification of what's
proposed. And then I'll try to grade as much as possible towards a
good conclusion.
Problem 3 (10 points)
Recasting the problem as "u=v" is worth 3 points. Then using the CR
equations is worth another 2. The remaining 5 points is for solving
the problem.
Problem 4 (10 points)
I think any attempts to solve this problem without using Cauchy's
Theorem (or, equivalently, some form of Green's Theorem) are not
likely to be successful. So 3 points for mentioning one of these forms
of solution and 2 points for the answer. 5 points for some explanation
of why the use of Green's Theorem or Cauchy's Theorem is relevant
which must include the word "analytic" or "holomorphic" (2 points) and
the phrase "piecewise smooth closed closed curve" (2 points).
The answer alone is worth 2 points.
Problem 5 (10 points)
I believe only antidifferentiation is likely to "solve" this
problem. 3 points for mentioning the technique, and then the remaining
points are awarded, as much as possible, in the evolution (?)
towards a solution. The answer is worth 2 points but only 1 point can
be lost if a student insists on incorrectly "simplifying" the
answer. I took off 2 points if the antiderivative is incorrect (I
didn't check the arithmetic then).
Problem 6 (10 points)
The only technique at this stage in the course which will be
successful is direct parameterization and computation. The beginning
of that is worth 3 points, and the balance of the credit is obtained
by carrying out the initial idea. Any incorrect "simplification" can
lose only 1 point. The answer is worth 2 points. I'll give 2 points
for noting that z4/4 has derivative z3 and the
integral of that part around the closed curve is 0. People who
don't "evaluate" e8Πi (it is 1) lose 1 point.
Problem 7 (10 points)
Here the length of the integrand is worth 2 points. 6 points for the
estimation of |f(z)|. Of this, 2 points for the top, and 4 points for
the bottom of the fraction defining f(z). Finally, the estimate and
the limiting argument can earn 2 points.
Problem 8 (10 points)
a) (6 points) Using some "test" is worth 2 points, and 3
points are for using the test correctly. Either the Ratio or the Root
Test are not difficult to complete. 1 point for the answer.
b) (2 points) 1 point for answering the absolute convergence question,
and 1 point for answering the divergence question.
c) (2 points) 1 point for answering the convergence question, and 1
point for giving a connection between absolute convergence and
convergence.
Problem 9 (10 points)
a) (5 points) 2 points for finding the Laplacian of the function. 1
point for the answer, and 2 points for supporting evidence.
b) (2 points) 1 point for "Yes" and 1 point for some supporting
reasoning.
c) (3 points) 1 point for "No" and 2 points for an example (1 for
exhibiting a valid example, and 1 point for some verification).
Problem 10 (10 points)
a) (5 points) 1 point for the picture in general, and then 1 point
for the vertices, 2 points for the edges (one straight edge and two curvy
[parabolic!] edges), and 1 point for the inside.
b) (5 points) 1 point for the picture in general, and then 1 point for
the vertices, 2 points for the edges (two straight edges and two
circular arcs), and 1 point for the inside.
Problem | #1 | #2 | #3 | #4 | #5 | #6 | Total |
---|---|---|---|---|---|---|---|
Max grade | 16 | 16 | 16 | 18 | 16 | 16 | 80 | Min grade | 6 | 2 | 0 | 0 | 0 | 0 | 17 | Mean grade | 11 | 11.88 | 8.31 | 5.31 | 9.13 | 7.13 | 52.75 | Median grade | 10.5 | 13 | 9.5 | 2.5 | 11 | 8 | 53.5 |
Numerical grades will be retained for use in computing the final
letter grade in the course.
Here are approximate letter grade assignments for this exam:
Letter equivalent | A | B+ | B | C+ | C | D | F |
---|---|---|---|---|---|---|---|
Range | [75,100] | [65,74] | [55,64] | [50,54] | [40,49] | [35,39] | [0,34] |
This was a take home exam. Certainly the questions were serious and difficult, but I intended that students who thought about the questions would be able to solve them, helped by the longer time they had to think and consult references. I adjusted the letter grade "bins" as described above to take into account the difficulty. I would give this exam to students in an appropriate course at any college I know. Here are some things noticed as I read student answers. My comments may be helpful to you in the future.
If z is not equal to ±i explain briefly why there must be such a curve.A number of students did not answer this question. Other matters were discussed, but the question was not answered.
Show that there is such an entire function in this case.Many students just assumed there was an entire f with Re(f)=u and did not explain their assertion.
Grading guidelines
The grader will read only what is written and not attempt to guess or
read the mind of the student.
The student should solve the problem given and should not invent
another problem and request credit for working on that problem.
Problem 1 (16 points)
3 points for location of the singularities (some explanation should be
offered).
4 points for the discussion of the singularity at 0.
9 points for the discussion of the non-zero singularities: 3 points
for identifying the type of singularity (2 for some supporting
reason), 2 for the order of the pole, and 4 of these points for the
residue calculation.
Problem 2 (16 points)
2 points for the contour; 4 points for the residue computation; 3
points for the limit of the big semicircle; 3 points for the limit of
small semicircle; 4 points for putting together the two intervals and
the residue to get the result.
Problem 3 (16 points)
a) 4 points for getting the Laurent series for g(z).
b) 4 points for explaining why g(z) has a pole, and 4 points for
explaining that only a finite number of the Laurent coefficients are
non-zero.
c) 4 points for applying the previous information to show that f(z) is
a non-constant polynomial.
Problem 4 (18 points)
a) 6 points, with 2 for starting some strategy which will be
successful.
b) 6 points, with a Cauchy formula worth 3 of them.
c) 6 points, with a suggestion of a valid example worth 2, 2 more
points for checking the limiting behavior of the function values, and
the final 2 points for the derivative behavior.
Problem 5 (18 points)
a) 4 points. Some pictures and some supporting discussion are
needed for full credit.
b) 6 points for discussion of A(1), and then 2 points for
"transporting" this to a more general discussion.
c) 6 points: 2 points for a valid suggestion of a domain, and 4 points
for supporting reasoning. (–2 if the domain is not maximal, and
–2 if the domain is not open).
Problem 6 (16 points)
8 points for explaining why a harmonic conjugate exists, and the other
8 points for explaining why the resulting entire function is constant.
Problem | #1 | #2 | #3 | #4 | #5 | #6 | #7 | #8 | #9 | #10 | Total |
---|---|---|---|---|---|---|---|---|---|---|---|
Max grade | 20 | 20 | 20 | 20 | 20 | 14 | 20 | 20 | 18 | 20 | 156 | Min grade | 5 | 10 | 11 | 0 | 1 | 0 | 0 | 0 | 0 | 0 | 40 | Mean grade | 16.5 | 15.31 | 14.56 | 9.25 | 15.88 | 6.63 | 14.69 | 12.94 | 5.56 | 8.63 | 119.04 | Median grade | 18.5 | 15.5 | 14 | 10 | 17 | 5 | 16 | 13.5 | 0 | 9.5 | 133 |
Numerical grades will be retained for use in computing the final
letter grade in the course.
Here are approximate letter grade assignments for this exam:
Letter equivalent | A | B+ | B | C+ | C | D | F |
---|---|---|---|---|---|---|---|
Range | [150,200] | [130,149] | [110,129] | [100,109] | [80,99] | [70,79] | [0,69] |
Grading guidelines
Minor errors (such as a missing factor in a final answer, sign error,
etc.) were penalized minimally. Students whose errors materially
simplify the problem were not be eligible for most of the
problem's credit.
The grader will read only what is written and not attempt to guess or
read the mind of the student.
The student should solve the problem given and should not invent
another problem and request credit for working on that problem.
Problem 1 (20 points)
6 points for the residue computation. 8 points for the contour and
integral estimation, and then 6 points for putting everything
together.
Problem 2 (20 points)
a) 6 points: 3 points for each equation (1 point for the answer and 2
for some reasoning).
b) 9 points: 3 points for an answer and 6 points for supporting
evidence.
c) 5 points for all answers (2 points) with some supporting
computation shown (3 points).
Problem 3 (20 points)
a) 5 points: the image of p is worth 1 point; each boundary curve is
worth 2 points. One curve should be a straight line, and the other
should be close to a circle with the correct center and radius.
b) 5 points: the image of p is worth 1 point; each boundary curve is
worth 2 points. One curve should be a ray along the negative real
axis, and the other should be a parabola with approximately the
correct vertex and axis of symmetry.
c) 5 points: the image of p is worth 1 point; each boundary curve is
worth 2 points. Each curve should be a circle with the correct center
and radius.
d) 5 points: the image of p is worth 1 point; each boundary curve is
worth 2 points. Each boundary curve should be a straight line with the
correct slope (0!) and location.
Problem 4 (20 points)
An appropriate formula connecting f and f´´ is worth 5
points. Then using it is worth 10 points, and getting exactly the
correct result is worth the last 5 points.
Problem 5 (20 points)
A use of Rouché's Thoerem would earn 8 points, and then
completing the problem earns the other 12 points. Other verifications
will be assessed appropriately (for example, a direct use of the
Argument Principle could be tried).
Problem 6 (20 points)
a) 6 points: false (1 point); example (2 points); fixup with
f´≠0 (3 points).
b) 7 points: false (1 point); example (3 points); fixup with
interior of C inside U (3 points).
c) 7 points: false (1 point); example (3 points); fixup with
convergence up to a boundary or singular point (3 points).
Problem 7 (20 points)
a) 8 points for using the Cauchy-Riemann equations.
b) 12 points: 4 points for verification of harmonicity, 4 points for a
harmonic conjugate, and 4 points for writing a function of z.
Problem 8 (20 points)
a) (9 points) The integral of f(z)/z is worth 4 points and can be
evaluated with the Cauchy integral formula. The integral of
f(z)/(z-i)2 is worth 5 points and 1 point of that is
reserved for noticing that the curve winds (!) around i twice and then
using this information to contribute to the answer.
b) (11 points) There are 3 singularities inside the circle (2
points). Finding the residue correctly at one singularity is worth 3
points, and then at the others, and the others together are worth 4
points. Assembling the answer is worth 2 points. Only noticing the
pole at 0 is worth 1+3+1=5 points.
Problem 9 (20 points)
A viable approach earns 8 points (for example, some integral
formula). The balance is earned by carrying it out.
Problem 10 (20 points)
a) (10 points) 7 points for the non-zero coefficients (1 each for each
coefficient and term, and 5 for the process); 3 points for an answer
to the convergence question.
b) (10 points) 7 points for the non-zero coefficients (1 each for each
coefficient and term, and 5 for the process); 3 points for an answer
to the convergence question (-1 if the distance is not to Π/2).
Maintained by
greenfie@math.rutgers.edu and last modified 5/10/2010.
Course grades
I computed a "figure of metrit" for each student. I did this by
adding the exam grades, five-sixths of the Entrance Exam gradde, and
five-elevenths of the total homework points. Then I compared this
with numbers obtained by proportioning the sums of the letter bin
boundaries for the three exams.