1.
[0 1 1]
[1 0 1]
[1 1 0]
[1 1 0]-[0 1 1]=[1 0 -1] = v
[1 0 1]-[0 1 1]= [1 -1 0] = u
u x v = 
|1 -1 0|
|1  0 -1|
= [1 1 1]
1(x-0)+1(y-1)+1(z-1)=0
x+y-1+z-1=0
x+y+z-2=0
x+y+z=2

2.
r(t)= [1 1 0]+t[0 2 4]
x+y+z=14
x(t) = 1
y(t) = 1+2t
z(t) = 4t
1+(1+2t)+4t=14
1+1+2t+4t=14
2+6t=14
t=2, plug into vec-valued func
[1 5 8] = Ans