MIDTERM 1 FOR Multivariable Calculus, Math 251(22-24), FALL 2020, Dr. Z.
NAME:Jiahe Li
RUID:200005714
EMAIL:jl2669@roseprogram.rutgers.edu
BELOW WRITE THE LIST OF THE ANSWERS
Answer[ 1 ]=Does not exist (WONG ANS. and WAY, -10 POINTS)
Answer[ 2 ]=Increasing
Answer[ 3 ]=3
Answer[ 4 ]=(0,5)
Answer[ 5 ]=0
Answer[ 6 ]=Does not exist
Answer[ 7 ]=Does not exist
Answer[ 8 ]=(0,0)
Answer[ 9 ]=28
Answer[ 10 ]=(0,7,0)
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Dear Jiahe,
You forgot to change the 0's into 1's, but even then most of the answers are wrong. Please take the make-up. I will not give you a grade.
Instructions: Download this file with its original name, mt1.txt, then rename it, in your computer
mt1FirstLast.txt
Edit it with your answers and solutions
USING COMPUTEREZE: e.g.: x times y IS x*y, x to the power y is x^y
and Email DrZcalc3@gmail.com, 80 minutes (or sooner) after starting (for most people 10:00am, Oct. 15)
Subject: mt1
with an attachment. YOU MUST NAME IT EXACTLY
mt1FirstLast.txt
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For each of the questions you MUST first figure, YOUR version, with the following convention
For i=1,2,3,4,5,6,7,8,9 , a[i]:= The i-th digit of your RUID, BUT of it is zero make it 1
Example: RUID=413200125;
a[1] = 4, a[2] = 1, a[3] = 3, a[4] = 2, a[5] = 1, a[6] = 1, a[7] = 1, a[8] = 2, a[9] = 5
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HERE WRITE THE ACTUAL a[i]
a[1]= 2 , a[2]= 0 , a[3]= 0 , a[4]= 0 , a[5]= 0, a[6]= 5, a[7]= 7, a[8]= 1, a[9]= 4
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Problem 1:
Find dz/dy at the point (1,1,1) if z(x,y) is given implicitly by the equation
x^a[1]+y^a[2]+z^a[3]+a[5]*x*y*z^2 = 3+a[5]
With my RUID data the question is
Find dz/dy at the point (1,1,1) if z(x,y) is given implicitly by the equation
x^2+y^0+z^0+0*x*y*z^2 = 3+0
Here is how I do it (Explain everything)
The equation is x^2-1=0, x=+-1, it doesn't contain z and y. So dz/dy doesn't exist.
Ans.: doesn't exist.
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Problem 2:
Suppose that grad(f)(P)=. Is f increasing or decreasing at the direction ?
With my RUID data the question is
Suppose that grad(f)(P)=<2,0,9>. Is f increasing or decreasing at the direction <2,0,0>?
Here is how I do it (Explain everything)
sqrt(2^2)=2
so the unit vector is <2/2,0,0>=<1,0,0>
<2,0,9>.<1,0,0>=2>0
so f increasing at this direction
Ans.: Increasing
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Problem 3:
Find the directional derivative of the function f(x,y,z)
x^3*a[6]+y^3*a[3]+z^3*a[8]
At the point P=(1,-1,1) in the direction pointing to Q=(1,-1,3)
With my RUID data the question is
Find the directional derivative of the function f(x,y,z)
x^3*5+y^3*0+z^3*1
At the point P=(1,-1,1) in the direction pointing to Q=(1,-1,3)
Here is how I do it (Explain everything)
The function is 5*x^3+z^3, <5*x^3,0, z^3>
The gradient is <15*x^2,0,3*z^2>
When P=(1,-1,1),the gradient is <15,0,3>
The vector is <1-1, -1-(-1),3-1>=<0,0,2>
sqrt(2^2)=2
The unit vector is <0,0,2/2>=<0,0,1>
The directional derivative is <0,0,1>.<15,0,3>=3
Ans.:3
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Problem 4:
Find a saddle point of the function f(x,y)=
exp(x-a[4])-(x-a[4])*exp(y-a[6])
If there is no saddle point, write in the Answers: "Does Not exist". Explain what you are doing
With my RUID data the question is
Find a saddle point of the function f(x,y)=exp(x)-x*exp(y-5)
If there is no saddle point, write in the Answers: "Does Not exist". Explain what you are doing
Here is how I do it (Explain everything)
f_x(x,y)=exp(x)-exp(y-5)
f_y(x,y)=-x*exp(y-5)
If both of them are 0,
x=y-5, x=0, y=5
So the critical point is (0,5)
f_xx(x,y)=exp(x)
f_yy(x,y)=-x*exp(y-5)
f_xy(x,y)=-exp(y-5)
For (0,5)
D=1*0-1=0
So the test fails.
By graphing, we found that this is a saddle point.
Ans.:(0,5)
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Problem 5:
Let f(x,y) be the function
a[4]*x + a[7]*y + a[2]
Find the ABSOLUTE MINIMUM VALUE of f(x,y) INSIDE the TRIANGLE whose VERTICES ARE
A = [a[1], a[2]], B = [a[3], a[4]], C = [a[5], a[6]]
With my RUID data the question is
Let f(x,y) be the function 7*y
Find the ABSOLUTE MINIMUM VALUE of f(x,y) INSIDE the TRIANGLE whose VERTICES ARE
A = [2, 0], B = [0, 0], C = [0, 5]
Here is how I do it (Explain everything)
Because there are only one variable, we only need to minimize it.
When it's on AB, y minimize, it's 0
Ans.:0
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Problem 6:
Let f(x,y) be the function
(x^2*a[4]^2-y^2*a[5]^2)/(x*a[4]-y*a[5])
Find the LIMIT of f(x,y) as (x,y) goes to the point [a[5],a[4]], or show that it does not exist
With my RUID data the question is
Let f(x,y) be the function
(x^2*0^2-y^2*0^2)/(x*0-y*0)
Find the LIMIT of f(x,y) as (x,y) goes to the point [a[5],a[4]], or show that it does not exist
Here is how I do it (Explain everything)
The function is 0/0 doesn't exist.
Ans: Does not exist
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Problem 7:
Find the curvature of the curve
r(t) = [a[1], a[2]*t, a[3]*t^2]
At the point (a[1],0,0)
With my RUID data the question is
Find the curvature of the curve r(t) = [2, 0, 0]
At the point (2,0,0)
Here is how I do it (Explain everything)
Because this is not a curve, it's just a point. So there are no curvature.
Ans: Does not exist
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Problem 8:
A particle is moving in the plane with ACCELERATION given by
[-a[1]*sin(t), -a[2]*cos(t)]
At time t=0 its position is , [0, a[2]]
and its velocity is , [a[1], 0]
Where is it located at time , t = Pi
With my RUID data the question is
A particle is moving in the plane with ACCELERATION given by
[-2*sin(t), 0]
At time t=0 its position is , [0, 0]
and its velocity is , [2, 0]
Where is it located at time , t = Pi
Here is how I do it (Explain everything)
int([-2*sin(t),0])=[2*cos(t),0]+C
When t=0,
[2,0]+C=[2,0],C=0
So the speed is [2*cos(t),0]
int([2*cos(t),0])=[2*sin(t),0]+C
When t=0,
[0,0]+C=[0,0], C=0
So the position is [2*sin(t),0]
When t=pi
The position is (0,0)
Ans: (0,0)
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Problem 9:
A certain function depends on variables x and y
Right now the rate of change of the function with respect to x is, a[5]
and the rate of change of the function with respect to y is, a[7]
Both x and y depend on time
Right now the rate of change of x with respect to time is, a[1]
and the rate of change of y with respect to time is, a[9]
How fast is the function changing right now?
With my RUID data the question is
A certain function depends on variables x and y
Right now the rate of change of the function with respect to x is, 0
and the rate of change of the function with respect to y is, 7
Both x and y depend on time
Right now the rate of change of x with respect to time is, 2
and the rate of change of y with respect to time is, 4
How fast is the function changing right now?
Here is how I do it (Explain everything)
df/dx=0, df/dy=7, dx/dt=2, dy/dt=4
df/dt= df/dx*dx/dt+ df/dy*dy/dt=7*4=28
Ans:28
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Problem 10:
Find the point of intersection of the three planes
x = a[5], y = a[7], z = a[3]
With my RUID data the question is
Find the point of intersection of the three planes
x = 0, y = 7, z = 0
Here is how I do it (Explain everything)
The point that follows x = 0, y = 7, z = 0 is (0,7,0)
Ans:(0,7,0)