MIDTERM 1 FOR Multivariable Calculus, Math 251(22-24), FALL 2020, Dr. Z.
NAME:Fayed Raza
RUID: 192002683
EMAIL: fr247@rutgers.edu
BELOW WRITE THE LIST OF THE ANSWERS
Answer[ 1 ]= -9y^8/2z
Answer[ 2 ]= Increasing
Answer[ 3 ]= 84/sqrt(96)
Answer[ 4 ]= Does Not exist
Answer[ 5 ]= 9
Answer[ 6 ]= 0
Answer[ 7 ]= 36/81
Answer[ 8 ]= [2t - 2, 0]
Answer[ 9 ]= 4
Answer[ 10 ]= (0,6,2)
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Instructions: Download this file with its original name, mt1.txt, then rename it, in your computer
mt1FirstLast.txt
Edit it with your answers and solutions
USING COMPUTEREZE: e.g.: x times y IS x*y, x to the power y is x^y
and Email DrZcalc3@gmail.com, 80 minutes (or sooner) after starting (for most people 10:00am, Oct. 15)
Subject: mt1
with an attachment. YOU MUST NAME IT EXACTLY
mt1FirstLast.txt
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For each of the questions you MUST first figure, YOUR version, with the following convention
For i=1,2,3,4,5,6,7,8,9 , a[i]:= The i-th digit of your RUID, BUT of it is zero make it 1
Example: RUID=413200125;
a[1] = 4, a[2] = 1, a[3] = 3, a[4] = 2, a[5] = 1, a[6] = 1, a[7] = 1, a[8] = 2, a[9] = 5
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HERE WRITE THE ACTUAL a[i]
a[1]= 1 , a[2]= 9, a[3]= 2, a[4]=0 , a[5]= 0, a[6]= 2, a[7]= 6, a[8]=8 , a[9]= 3
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Problem 1:
Find dz/dy at the point (1,1,1) if z(x,y) is given implicitly by the equation
x^a[1]+y^a[2]+z^a[3]+a[5]*x*y*z^2 = 3+a[5]
With my RUID data the question is
Find dz/dy at the point (1,1,1) if z(x,y) is given implicitly by the equation
x^1+y^9+z^2 = 3
Here is how I do it (Explain everything)
Ans.:
Fz = 2z
Fy = 9y^8
dz/dy = -Fy/Fz = -9y^8/2z
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Problem 2:
Suppose that grad(f)(P)=. Is f increasing or decreasing at the direction ?
With my RUID data the question is
Here is how I do it (Explain everything)
Suppose that grad(f)(P)=<1,0,8>. Is f increasing or decreasing at the direction <1,2,0>?
Ans.:
<1,2,0> * <1,0,8> = 1 + 0 + 0 = 1 Increasing since 1 > 0
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Problem 3:
Find the directional derivative of the function f(x,y,z)
x^3*a[6]+y^3*a[3]+z^3*a[8]
At the point P=(1,-1,1) in the direction pointing to Q=(1,-1,3)
With my RUID data the question is
Find the directional derivative of the function f(x,y,z)
x^6+y^6+z^24
Here is how I do it (Explain everything)
1/sqrt(11) <1,-1,3>
<6x^5,6y^5, 24z^23> -> <6,-6,24> * 1/sqrt(96) <1,-1,3> = 84/sqrt(96)
Ans.:
11/sqrt(11)
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Problem 4:
Find a saddle point of the function f(x,y)=
exp(x-a[4])-(x-a[4])*exp(y-a[6])
If there is no saddle point, write in the Answers: "Does Not exist". Explain what you are doing
With my RUID data the question is
Find a saddle point of the function f(x,y)=
exp(x)-(x)*exp(y-2)
Here is how I do it (Explain everything)
fx= exp(x)-exp(y-2)
x=y-2
exp(x)=exp(2-2)
exp(x)=1
x = ln(1)
Fy = -(y-2)*exp(y-2)
y=2
(0,2)
fxx= exp(x) = 1
fxy = 0
Fyy = -(x)*exp(y-2) = 0
Fxxfyy - fxy^2 = 0-0 = 0 No saddle point since d = 0
Does Not exist
Ans.:
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Problem 5:
Let f(x,y) be the function
a[4]*x + a[7]*y + a[2]
Find the ABSOLUTE MINIMUM VALUE of f(x,y) INSIDE the TRIANGLE whose VERTICES ARE
A = [a[1], a[2]], B = [a[3], a[4]], C = [a[5], a[6]]
With my RUID data the question is
Let f(x,y) be the function
6*y + 9
Find the ABSOLUTE MINIMUM VALUE of f(x,y) INSIDE the TRIANGLE whose VERTICES ARE
A = [9, 9], B = [2, 0], C = [0, 2]]
Here is how I do it (Explain everything)
Fx = 0
Fxx =0
Fyy =0
Fxy = 0
Fy = 6
(0,6)
0-0
D=0
9 9 = 54 + 9 = 63
2 0 = 9
0 2 = 21
Ans.:
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Problem 6:
Let f(x,y) be the function
(x^2*a[4]^2-y^2*a[5]^2)/(x*a[4]-y*a[5])
Find the LIMIT of f(x,y) as (x,y) goes to the point [a[5],a[4]], or show that it does not exist
With my RUID data the question is
Let f(x,y) be the function
(-y^2*1^2)/(x*2-y)
Find the LIMIT of f(x,y) as (x,y) goes to the point [0,0], or show that it does not exist
Here is how I do it (Explain everything)
r^2cos0^2/(2rsin0 - rcos0)= lim r-> 0 rcos0^2 /(2sin0-cos0) = 0
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Problem 7:
Find the curvature of the curve
r(t) = [a[1], a[2]*t, a[3]*t^2]
At the point (a[1],0,0)
With my RUID data the question is
Find the curvature of the curve
r(t) = [1, 9*t, 2*t^2]
At the point (1,0,0)
Here is how I do it (Explain everything)
R'(t) = [0,9,4t]
R''t = [0,0,4]
I j k
0 9 4t
0 0 4
36i-0j-0k
36/(16 (0)^2 + 81) = 36/81
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Problem 8:
A particle is moving in the plane with ACCELERATION given by
[-a[1]*sin(t), -a[2]*cos(t)]
At time t=0 its position is , [0, a[2]]
and its velocity is , [a[1], 0]
Where is it located at time , t = Pi
With my RUID data the question is
A particle is moving in the plane with ACCELERATION given by
[-*sin(t), -9*cos(t)]
At time t=0 its position is , [0, 9]
and its velocity is , [1, 0]
Where is it located at time , t = Pi
Here is how I do it (Explain everything)
1 = -cos(0) + c
c= 2
0 = -9sin(0) + C
vt(t) = [-sin(t) + 2, -9*cos(t)]
0 = cos(t) + 2t + C
0 = 1 + C
C =-1
v(t) = -9sint(t) + C
0 = C
[cos(t) + 2t - 1, -9sint(t)]
[cos(pi) + 2t - 1, -9sint(pi)]
[2t - 2, 0]
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Problem 9:
A certain function depends on variables x and y
Right now the rate of change of the function with respect to x is, a[5]
and the rate of change of the function with respect to y is, a[7]
Both x and y depend on time
Right now the rate of change of x with respect to time is, a[1]
and the rate of change of y with respect to time is, a[9]
How fast is the function changing right now?
With my RUID data the question is
A certain function depends on variables x and y
Right now the rate of change of the function with respect to x is, 0
and the rate of change of the function with respect to y is, 1
Both x and y depend on time
Right now the rate of change of x with respect to time is, 4
and the rate of change of y with respect to time is, 5
How fast is the function changing right now?
Here is how I do it (Explain everything)
(4-0) = 4
(5-1) = 4
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Problem 10:
Find the point of intersection of the three planes
x = a[5], y = a[7], z = a[3]
With my RUID data the question is
Find the point of intersection of the three planes
x = 0, y = 6, z = 2
Here is how I do it (Explain everything)
(0,6,2)
All plane will touch at (0,6,2)