MIDTERM 1 FOR Multivariable Calculus, Math 251(22-24), FALL 2020, Dr. Z.
NAME:
Aayushi Kasera
RUID:
193008020
EMAIL:
amk408@scarletmail.rutgers.edu
BELOW WRITE THE LIST OF THE ANSWERS
Answer[ 1 ]=-2
Answer[ 2 ]= decreasing
Answer[ 3 ]= 6
Answer[ 4 ]=does not exist
Answer[ 5 ]=-10
Answer[ 6 ]=2
Answer[ 7 ]=54/729
Answer[ 8 ]=(0,-1)
Answer[ 9 ]=10
Answer[ 10 ]=(1,1,1)
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Instructions: Download this file with its original name, mt1.txt, then rename it, in your computer
mt1FirstLast.txt
Edit it with your answers and solutions
USING COMPUTEREZE: e.g.: x times y IS x*y, x to the power y is x^y
and Email DrZcalc3@gmail.com, 80 minutes (or sooner) after starting (for most people 10:00am, Oct. 15)
Subject: mt1
with an attachment. YOU MUST NAME IT EXACTLY
mt1FirstLast.txt
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For each of the questions you MUST first figure, YOUR version, with the following convention
For i=1,2,3,4,5,6,7,8,9 , a[i]:= The i-th digit of your RUID, BUT of it is zero make it 1
Example: RUID=413200125;
a[1] = 4, a[2] = 1, a[3] = 3, a[4] = 2, a[5] = 1, a[6] = 1, a[7] = 1, a[8] = 2, a[9] = 5
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HERE WRITE THE ACTUAL a[i]
a[1]= , a[2]= , a[3]= , a[4]=0 , a[5]= , a[6]= , a[7]= , a[8]= , a[9]=
1,9,3,1,1,8,1,2,1
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Problem 1:
Find dz/dy at the point (1,1,1) if z(x,y) is given implicitly by the equation
x^a[1]+y^a[2]+z^a[3]+a[5]*x*y*z^2 = 3+a[5]
With my RUID data the question is
x+y^9+z^3+xyz^2=4
Here is how I do it (Explain everything)
Ans.:
x+y^9+z^3+xyz^2=4
x+y^9+z^3+xyz^2=3
9y^8+3z^2(dz/dy)+2xyz(dz/dx)+xz^2=0
Dz/dy=-9y^8-xz^2
Dz/dy=(-9y^8-xz^2)/(3z^2+2xyz)
=(-9-1)/(5)
-2
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Problem 2:
Suppose that grad(f)(P)=. Is f increasing or decreasing at the direction ?
With my RUID data the question is
grad(f)(P)=<1,-1,3> , v=<1,3,-1>
Here is how I do it (Explain everything)
Ans.:
grad(f)(P)=<1,-1,3> , v=<1,3,-1>
|v|=sqrt(11)
u=<1/sqrt(11),3/sqrt(11),-1/sqrt(11)>
Dot product of the grad(F) and direction vector
<1,-1,3>.<1/sqrt(11),3/sqrt(11),-1/sqrt(11)>
=1/sqrt(11)-3/sqrt(11)-3/sqrt(11)
-8/sqrt(11)
Since the dot product is negative, it is decreasing
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Problem 3:
Find the directional derivative of the function f(x,y,z)
x^3*a[6]+y^3*a[3]+z^3*a[8]
At the point P=(1,-1,1) in the direction pointing to Q=(1,-1,3)
With my RUID data the question is
f(x,y,z)=x^24+y^9+z^6
Here is how I do it (Explain everything)
Ans.:
F_x= 24x^23
F_y=9y^8
f_z=6z^5
grad_f=<24x^23,9y^8,6z^5>
grad_f(1,-1,1)=<24,-9,6>
v=Q-P=<0,0,2>
|v|=2
u=<0,0,1>
Take the dot product of grad_f.u
6
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Problem 4:
Find a saddle point of the function f(x,y)=
exp(x-a[4])-(x-a[4])*exp(y-a[6])
If there is no saddle point, write in the Answers: "Does Not exist". Explain what you are doing
With my RUID data the question is
f(x,y)=exp(x-1)-(x-1)*exp(y-8))
Here is how I do it (Explain everything)
Ans.:
F_x=exp(x-1)-exp(y-8)
f_y=-(x-1)exp(y-8)
Find critical points
f_x=0
x-1=y-8
x-y=-7
x+7=y
y=8
f_y=0
x=1
CP=(1,8)
f_xx=exp(x-1)
=1
f_yy=-(x-1)exp(y-8)
=0
f_xy=-exp(y-8)
=-1
D=1
Since D>0,f_xx>0
(1,8) is a local minimum
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Problem 5:
Let f(x,y) be the function
a[4]*x + a[7]*y + a[2]
Find the ABSOLUTE MINIMUM VALUE of f(x,y) INSIDE the TRIANGLE whose VERTICES ARE
A = [a[1], a[2]], B = [a[3], a[4]], C = [a[5], a[6]]
With my RUID data the question is
Let f(x,y) be the function
x + y + 9
Find the ABSOLUTE MINIMUM VALUE of f(x,y) INSIDE the TRIANGLE whose VERTICES ARE
A = [1,9], B = [3,1], C = [1,8]
Here is how I do it (Explain everything)
f_x=y
f_y=x
f_xy=1
f(x,1)=x+10
Points can be -10, 11, 18
f(1,y)=y+10
Points are, -10, 11, 18
f(x,x)=2x+9
So, points are x=-9/2, 11, 25
Ans.:
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Problem 6:
Let f(x,y) be the function
(x^2*a[4]^2-y^2*a[5]^2)/(x*a[4]-y*a[5])
Find the LIMIT of f(x,y) as (x,y) goes to the point [a[5],a[4]], or show that it does not exist
With my RUID data the question is
Let f(x,y) be the function
(x^2-y^2)/(x-y)
Find the LIMIT of f(x,y) as (x,y) goes to the point [1,1], or show that it does not exist
Here is how I do it (Explain everything)
f(x,y)=(x^2-y^2)/(x-y)
f(x,y)=x+y
lim(x,y)->(1,1)(x+y)
=2
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Problem 7:
Find the curvature of the curve
r(t) = [a[1], a[2]*t, a[3]*t^2]
At the point (a[1],0,0)
With my RUID data the question is
Find the curvature of the curve
r(t) = [1, 9t, 3t^2]
At the point (1,0,0)
Here is how I do it (Explain everything)
R'(t)=<0,9,0>
R"(t)=<0,0,0>
R'(t)xR"(t)
<0,9,0>x<0,0,6>
=<54,0,0>
|R'(t)xR"(t)|=54
|R'(t)|=9
|R'(t)|^3=9^3
Curvature kuppa= 54/9^3
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Problem 8:
A particle is moving in the plane with ACCELERATION given by
[-a[1]*sin(t), -a[2]*cos(t)]
At time t=0 its position is , [0, a[2]]
and its velocity is , [a[1], 0]
Where is it located at time , t = Pi
With my RUID data the question is
A particle is moving in the plane with ACCELERATION given by
[-sin(t), -9cos(t)]
At time t=0 its position is , [0, 9]
and its velocity is , [1, 0]
Where is it located at time , t = Pi
Here is how I do it (Explain everything)
a(t)=-sin(t)i-9cos(t)j
Integrate a(t)=v(t)=cos(t)i-9sin(t)j+c
v(0)=i
v(0)=cos(0)i-9sin(0)j+c
i=I+c
c=0
v(t)=cos(t)i-9sin(t)j
x(t)= integrate v(t)
integrate v(t)= x(t)=sin(t)i+9cos(t)j+c
x(0)=9j
x(0)=j+c
c=8j
x(t)=sin(t)i+(9cos(t)+8)j+c
sin(pi)I+(9cos(pi)+8)j
=-1j
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Problem 9:
A certain function depends on variables x and y
Right now the rate of change of the function with respect to x is, a[5]
and the rate of change of the function with respect to y is, a[7]
Both x and y depend on time
Right now the rate of change of x with respect to time is, a[1]
and the rate of change of y with respect to time is, a[9]
How fast is the function changing right now?
With my RUID data the question is
Here is how I do it (Explain everything)
Df/dx=1
Dy/dt=1
Df/dy=1
Dy/dt=9
Ans:1+9
10
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Problem 10:
Find the point of intersection of the three planes
x = a[5], y = a[7], z = a[3]
With my RUID data the question is
x = 1, y = 1, z = 1
Here is how I do it (Explain everything)
a=<1,0,0>
b=<0,1,0>
c=<0,0,1>
aXb=0