MIDTERM 1 FOR Multivariable Calculus, Math 251(22-24), FALL 2020, Dr. Z.
NAME: Khush Tated
RUID: 192002457
EMAIL:kt514@scarletmail.rutgers.edu
BELOW WRITE THE LIST OF THE ANSWERS
Answer[ 1 ]= -2.5
Answer[ 2 ]= Decreasing
Answer[ 3 ]= 15
Answer[ 4 ]= Does not exist
(WRONG ANS., BUT OTHERWISE PERFECT, NEGATIVE D MEANS IT IS A SADDLE POINT, -3 POINTS)
Answer[ 5 ]= 18
(WRONG ANS., RIGHT WAY! CARELESS ERROR, f(2,1)=15, -3 POINTS)
Answer[ 6 ]= 0 (WRONG ANS. WRONG WAY, -10 POINTS)
Answer[ 7 ]= 4/81
Answer[ 8 ]= <0, -9>
Answer[ 9 ]= 29
Answer[ 10 ]= (1, 4, 2)
SCORE: 84 POINTS (OUT of 100)
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Instructions: Download this file with its original name, mt1.txt, then rename it, in your computer
mt1FirstLast.txt
Edit it with your answers and solutions
USING COMPUTEREZE: e.g.: x times y IS x*y, x to the power y is x^y
and Email DrZcalc3@gmail.com, 80 minutes (or sooner) after starting (for most people 10:00am, Oct. 15)
Subject: mt1
with an attachment. YOU MUST NAME IT EXACTLY
mt1FirstLast.txt
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For each of the questions you MUST first figure, YOUR version, with the following convention
For i=1,2,3,4,5,6,7,8,9 , a[i]:= The i-th digit of your RUID, BUT of it is zero make it 1
Example: RUID=413200125;
a[1] = 4, a[2] = 1, a[3] = 3, a[4] = 2, a[5] = 1, a[6] = 1, a[7] = 1, a[8] = 2, a[9] = 5
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HERE WRITE THE ACTUAL a[i]
a[1] = 1, a[2] = 9, a[3] = 2, a[4] = 1, a[5] = 1, a[6] = 2, a[7] = 4, a[8] = 5, a[9] = 7
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Problem 1:
Find dz/dy at the point (1,1,1) if z(x,y) is given implicitly by the equation
x^a[1]+y^a[2]+z^a[3]+a[5]*x*y*z^2 = 3+a[5]
With my RUID data the question is x+y^9+z^2+1*x*y*z^2 = 3+1
Here is how I do it (Explain everything)
We need to differentiate everything with respect to y.
This becomes x + y^9 + x^2 + 1 + x*y*z^2 = 4
When differentiated with respect to y, this becomes
9y^8 + 2z * dz/dy + 2*x*y*z*dz/dy + xz^2 = 0
Now solve for dz/dy
-(9y^8 + x*z^2)/(2z + 2*x*y*z)
=-10/4 = -2.5
Ans.: -2.5
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Problem 2:
Suppose that grad(f)(P)=. Is f increasing or decreasing at the direction ?
With my RUID data the question is
grad(f)(P)=<1,-1,6>
Direction: <1, 2, -1>
Here is how I do it (Explain everything)
Take the dot product of the 2 vectors
1 -2 -6 = -1 -6 = -7
Due to a negative dot product, this is decreasing.
Ans.: Decreasing
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Problem 3:
Find the directional derivative of the function f(x,y,z)
x^3*a[6]+y^3*a[3]+z^3*a[8]
At the point P=(1,-1,1) in the direction pointing to Q=(1,-1,3)
With my RUID data the question is
x^3*2+y^3*2+z^3*5
At the point P=(1,-1,1) in the direction pointing to Q=(1,-1,3)
Here is how I do it (Explain everything)
Gradient is <6x^2, 6y^2, 15z^2>
PQ is <0, 0, 2>
Unit direction is <0, 0, 1>
Gradient at point P is <6, 6, 15>
Dot product of gradient and unit direction is 15.
Ans.:15
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Problem 4:
Find a saddle point of the function f(x,y)=
exp(x-a[4])-(x-a[4])*exp(y-a[6])
If there is no saddle point, write in the Answers: "Does Not exist". Explain what you are doing
With my RUID data the question is
exp(x-1)-(x-a1)*exp(y-2)
Here is how I do it (Explain everything)
Find Fx, Fy, Fxy
Fx = (exp)(x-1) - exp(y-2)
Fy = (x-1)(exp(y-2))
Fxy = -exp(y-2)
Critical point after setting Fx and Fy to 0 is 1,2
Fx(1,2) = 0
Fy(1,2) =0
Fxy(1, 2) = -1
Because the discriminant is -1, there is no saddle point.
Ans.: Does not exist
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Problem 5:
Let f(x,y) be the function
a[4]*x + a[7]*y + a[2]
Find the ABSOLUTE MINIMUM VALUE of f(x,y) INSIDE the TRIANGLE whose VERTICES ARE
A = [a[1], a[2]], B = [a[3], a[4]], C = [a[5], a[6]]
With my RUID data the question is
Function: x + 4y + 9 =f(x,y)
A = (1, 9)
B = (2, 1)
C = (1, 2)
Here is how I do it (Explain everything)
Fx = 1
Fy = 4
Fxy = 0
There are no critical points. We can look at the points located on the triangles
The absolute minimum value in this triangle is at (1, 2)
1 + 4(2) + 9.
Ans.: 18
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Problem 6:
Let f(x,y) be the function
(x^2*a[4]^2-y^2*a[5]^2)/(x*a[4]-y*a[5])
Find the LIMIT of f(x,y) as (x,y) goes to the point [a[5],a[4]], or show that it does not exist
With my RUID data the question is
(x^2*1-y^2*1)/(x-y) as it goes to (1,1)
Here is how I do it (Explain everything)
Subsitute (1, 1) = 0/0. Indeterminate
Let y = cx
(x^2 - c^2*x^2) / (x - c*x) / (x- c*x)
Simplify
x*(x-c) / (1-c). This limit depends on x. Let's go to polar
lim r goes to 0 of r^2 cos^2(theta) - r^2*sin^2(theta) / (r*costheta - r*isntehta)
= 0
Ans : 0
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Problem 7:
Find the curvature of the curve
r(t) = [a[1], a[2]*t, a[3]*t^2]
At the point (a[1],0,0)
With my RUID data the question is
r(t) = [1, 9*t, 2*t^2]
at (1, 0, 0)
Here is how I do it (Explain everything)
Find r'(t) = <0, 9, 4t> = <0, 9, 0> at relevant point
r''(t) = <0, 0, 4>
Cross product magnitude between r'(t) x (r'(t)) = <36, 0, 0>
Magnitude of r'(t) = 9
36 / 9^3 = 4/81
Ans: 4/81
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Problem 8:
A particle is moving in the plane with ACCELERATION given by
[-a[1]*sin(t), -a[2]*cos(t)]
At time t=0 its position is , [0, a[2]]
and its velocity is , [a[1], 0]
Where is it located at time , t = Pi
With my RUID data the question is
ACCELERATION = <-1*sin(t), -9*cos(t)>
velocity = <1, 0>
time = pi
Here is how I do it (Explain everything)
Integrate ACCELERATION with respect to t.
velocity = + c = < 1, 0>. C = 0
Integreate velocity with respect to t.
Position = + c = <0, 9>
So at t = pi, position is <0, -9>
Ans: <0, -9>
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Problem 9:
A certain function depends on variables x and y
Right now the rate of change of the function with respect to x is, a[5]
and the rate of change of the function with respect to y is, a[7]
Both x and y depend on time
Right now the rate of change of x with respect to time is, a[1]
and the rate of change of y with respect to time is, a[9]
How fast is the function changing right now?
With my RUID data the question is
Right now the rate of change of the function with respect to x is, 1
and the rate of change of the function with respect to y is, 4
Right now the rate of change of x with respect to time is, 1
and the rate of change of y with respect to time is, 7
Here is how I do it (Explain everything)
This is a chain rule question.
Multiply dz/dx *dx/dt = 1*1
Multiply dz/dy * dy/dt = 4*7
Add them together 29.
1 + 28 = 29
Ans: 29
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Problem 10:
Find the point of intersection of the three planes
x = a[5], y = a[7], z = a[3]
With my RUID data the question is
x = 1
y = 4
z = 2
Here is how I do it (Explain everything)
Because the x plane spans out in every direction from x = 2, y plane spans out from y = 4, and z spans out from z = 2,
the point of intersection if (1, 4, 2)
Ans: (1, 4, 2)