#ATTENDANCE QUIZ FOR LECTURE 23 of Dr. Z.'s Math454(02) Rutgers University # Please Edit this .txt page with Answers #Email ShaloshBEkhad@gmail.com #Subject: p23 #with an attachment called #p23FirstLast.txt #(e.g. p23DoronZeilberger.txt) #Right after finishing watching the lecture but no later than Dec. 4, 2020, 8:00pm THE NUMBER OF ATTENDANCE QUESTIONS WERE: 3 PLEASE LIST ALL THE QUESTIONS FOLLOWED, AFTER EACH, BY THE ANSWER # Question 1: Use Lagrange Inversion Formula to find an explicit expression for the coeff # of x^n in the power series of u(x) that satisfies the functional equation: # (i) u(x) = x*(1+u(x))^2 # (ii) u(x) = x*(1+u(x))^3 # (iii) u(x) = x*(1+u(x))^k (for any positive integer k) # Answer: # (i): # R(x) = 1/n * coeff of z^(n-1) in (1+z)^2 # 1/n * coeff of z in ((1+z)^2)^n = 1/n * (2n C n-1) # (ii): # R(x) = 1/n * coeff of z^(n-1) in (1+z)^3 # 1/n * coeff of z in (1+z)^3n = 1/n * (3n C n-1) # (iii): # R(x) = 1/n * coeff of z^(n-1) in (1+z)^k # 1/n * coeff of z in (1+z)^kn = 1/n * (kn C n-1) 1/n * coeff of z^n-1 (1+z)^2n # ---------------------------------------------------------------------------------------------------- # Question 2: Consider the function given above: # f(1) = 13, f(2) = 7, .... f(16 = 1 # (i) Draw this directed graph # Find the doubly rooted tree that is outputted by the joyal bijection # Check that it is as below: # [[1,13],[1,16], [2,7], [2,8], [3,15],[4,10], [4,11], [5,13], [6,7], [6,12],[6,16], [9,11],[10,12],[11,14],[15,16]], [13,5] # Answer: # 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 # 13 7 15 10 13 16 6 2 11 12 4 6 5 11 16 1 # 14 # | # 9 -> 11 -> 4 # | # 10 # | # 12 # | # 8 -> 2 -> 7 -> 6 -> 16 -> 1 -> 13 <-> 5 # | # 15 # | # 3 # Cycles: {5,13} # pi(5) = 13, pi(13) = 5 # 8 # | # 2 # | # 7 # | # 6 14 # | | # 3-> 15 -> 16 -> 12-> 10->4->11->9 # | # 1 # | # *13 -> 5** # ---------------------------------------------------------------------------------------------------- # Question 3: Finish this. Find the Pruffer Code (of length 11) of the original tree. # [2, 4, 11, 8, 7, 6, 10, 3, 6, 3, 2]