> NULL;
> #`Assumptions:` #`        1 :   All people in class were born in the US (For the sake of simplicity) Source: [https://www.behindthename.com/name/julian/top/united-states?type=sample]   ` #`        2 :  Assume all people in this class are between 18 and 30 years old (born from 1991-2003) for simplity [same source]` # #`        3 : Assume everyone has the same interest in math, regardless of name (For the sake of idealism) ` # #`        4:   How to get the ratio `                   #`Part 1: `                               #`Taking the following sum:`                                  #`   Julians` :=(∑)(`pj__n`*`bb__n`))                                  #`Where (a): pj__n` represents "Percent Julian at YEAR n"                                   #`           (b): bb__n` represents "Babies born in the US at YEAR n"                                                  #`Part 2:`                                #`Taking the following sum:`                                  #  conjugate(J ) =(∑)(`bb__n`)-((∑)`pj__n`*`bb__n`)=Total babies - Total Julians                                  #`Where bb__n`   , again,  represents "Babies born in the US at YEAR n"                                  #We get the total number of People born in the US from 1991-2003 who are not named Julian, denoted as  (J).               #Part 3 :                                 #We will start Create a recurrence, where:                                         # We have n=18 steps, therefore we generate a sequence Sample:= Seq(J[][n]  ,   n=1.. 18)          which appends a                                          #` Our first `conjugate(J[0])=J               #`Part 4`   #`                            #As there are 18 students in the classroom, we need to find K number of outcomes that have a total number of at least 2 Julians `                                 #`For ease of calculation, K is also equal to the total number of outcomes in which there are 1 Julian or 0 Julians, denoted as T`[0]  and T[1] respectively.                                 #`Let total probability =`(∑)(1-`T__n`/(Total people-n)) =(∑)(1-((conjugate(J)-n)!)/((Total people-n)!(Total people-n)))                                  ;
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