#ATTENDANCE QUIZ FOR LECTURE 2 of Dr. Z.'s Math336 Rutgers University\
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# Please Edit this .txt page with Answers\
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#Email  ShaloshBEkhad@gmail.com \
#Subject: p2\
#with an attachment called\
#p2FirstLast.txt\
#(e.g. p2DoronZeilberger.txt)\
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#Right after attending the lecture  but no later than  Tue., Sept. 7, 4:00pm, 2021, 4:00pm\
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LIST ALL THE ATTENDANCE QUESTIONS FOLLOWED BY THEIR ANSWERS\
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Q1. Who was Sir Ronald Ross, what was his claim to fame?\
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A1. He received the Nobel Prize for Physiology or Medicine for his work on the transmission of malaria. He found the malarial parasite in the gastrointestinal tract in mosquitoes in 1897, proving that malaria was transmitted by mosquitoes. \
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Q2. Copy maple code for a:=proc(n) without option remember, call it astupid.\
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A2. astupid:=proc(n):\
if n=0 then\
0:\
elif n=1 then\
1:\
elif n=2 then\
4:\
else 3*astupid(n-1)-3*astupid(n-2)+astupid(n-3):\
fi:\
end:
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seq(astupid(n),n=0..100);\
Took well over 30 minutes for the program to give me an output. \
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Q3. a1 = fifth digit in RUID (0), a2 = second digit in RUID (7), a3 = third digit in RUID (0)\
	USE MAPLE TO SOLVE differential equation y\'92(t)=a1*t^a2/y^a3, y(1) = a2\
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A3. dsolve(\{diff(y(t),t)=0*t^7/y(t)^0,y(1)=7\},y(t))\
                            y(t) = 7\
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Q4. Sir Ronald Ross's collaborator Hilda Hudson, what was her middle name?\
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A4. Her middle name was Phoebe.\
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Q5. #Let a1:=8th digit in your RUID (8)\
#Let a2:=your age (23)\
#Let a3:=your mother's age (53)\
#solve (using maple, the differential equation)\
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#a1*y''(t)+a2*y'(t)+a3*y(t)=0, subject to y(0)=1, y'(0)=0\
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A5. dsolve({8*D(D(y))(t)+23*D(y)(t)+53*y(t)=0,y(0)=1,D(y)(0)=0},y(t))
             23      (1/2)    /  23  \    /1      (1/2)  \
     y(t) = ---- 1167      exp|- -- t| sin|-- 1167      t|
            1167              \  16  /    \16            /

             /  23  \    /1      (1/2)  \
        + exp|- -- t| cos|-- 1167      t|
             \  16  /    \16            /

Q6. #Let a1:=your father's age (59)\
#Let a2:=your mother's age (53)\
#Let a3:=your younger sibling's age (20)\
#Let A be the 3 x 3 matrix [[a1, a2, a3], [a2, a3, a1], [a3, a2, a1]]\
#Find (in floating points) the SECOND largest eigenvalue (in absolute value) and the corresponding eigenvector)\
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A6.A:=Matrix([[59, 53, 20], [53, 20, 59], [20, 53, 59]])
                            [59  53  20]
                            [          ]
                       A := [53  20  59]
                            [          ]
                            [20  53  59]
evalf(Eigenvalues(A));
                         [&uminus0;33.]
                         [            ]
                         [    39.     ]
                         [            ]
                         [    132.    ]
Eigenvectors(A)[2]
                  [                      1169]
                  [1      1       uminus0----]
                  [                      1063]
                  [                          ]
                  [          112      40     ]
                  [1  uminus0---     ----    ]
                  [          53      1063    ]
                  [                          ]
                  [1      1            1     ]