Answers to the Math 336 Final

Rename this file

FirstLastFinal.txt

and mail to ShaloshBEkhad@gmail.com no later than Tue., Dec. 14, 2021.


MY NAME: Charles Forrest Griebell

MY RUID: 185007331


Ans. to 1: 1.618033988

Ans. to 2(a): Q=0 and Q=1 BUT NOT Q=2 because of carrying capacity            ;  Ans. to 2(b):  Q=1 is the only stable equilibrium because negative eigenvalue                       ; Ans to 2(c): Q(1000) = 0.9999999997


Ans. to 3(a): x=[0] and x=[3/2 - sqrt(105)/10] but NOT x=[3/2 + sqrt(105)/10] because of carrying capacity        ; Ans. to 3(b)    x= [3/2 - sqrt(105)/10] is the only stable equilibrium because abs less than 1           : Ans. to 3(c): x(1000) =  0.4753049232

Ans. to 4(a): Aa = 0.5000000000 at n=2                ; Ans. to 4(b): Aa = 0.5000000000 at n=1000                                  


Ans. to 5(a): Aa = 0.4989010989 at n=2                 ; Ans. to 5(b): Aa = 0.3974661800 at n=1000                                   

Ans. to 6: maple builtins 0.7478789082 = y(10000000000000000000000000000000000000000000000000000000000) DR. Z Orb way:   0.7478789080 = y(10000000000000000000000000000000000000000000000000000000000)

Ans. to 7(a): Removed = 0                   ; Ans. to 7(b): Removed = 923 (rounded down)                          ; Ans. to 7(c): Beta = 0.1 is the cutoff when N = 1000 and nu=100                     


Ans. to 8(a): 0.6823278038 is the height of horizontal asymptote                 ; Ans. to 8(b):   1.213411663  is the height of horizontal asymptote                     ; Ans. to 8(c): alpha = 7.39 is the largest 2-decimal value that still leads to a horizontal asymptote

Ans. to 9(a): 5.083333333 = N                  ; Ans. to 9(b): 0.6666666667 = C

Ans. to 10(a):  s[1] = 0.07692307692                ; Ans. to 10(b): s[9] = 0.1538461538