Problem | #1 | #2 | #3 | #4 | #5 | #6 | #7 | #8 | #9 | Total |
---|---|---|---|---|---|---|---|---|---|---|
Max grade | 12 | 8 | 10 | 12 | 12 | 12 | 7 | 10 | 14 | 89 | Min grade | 0 | 0 | 0 | 4 | 0 | 0 | 0 | 0 | 0 | 10 | Mean grade | 9.57 | 4.87 | 4.22 | 9.65 | 4.52 | 7.57 | 1 | 6 | 7.98 | 55.37 | Median grade | 10 | 5 | 3 | 10 | 5 | 0 | 0 | 6 | 10 | 54 |
The two versions of the exam had very similar statistical results.
Numerical grades will be retained for use in computing
the final letter grade in the course.
Here are approximate letter grade assignments for this exam:
Letter equivalent | A | B+ | B | C+ | C | D | F |
---|---|---|---|---|---|---|---|
Range | [85,100] | [80,84] | [70,79] | [65,69] | [55,64] | [50,54] | [0,49] |
Grading guidelines
Minor errors (such as a missing factor in a final answer, sign error,
etc.) will be penalized minimally. Students whose errors materially
simplify the problem will not be eligible for most of the
problem's credit.
The grader will read only what is written and not attempt to guess or
read the mind of the student.
The student should solve the problem given and should not invent
another problem and request credit for working on that problem.
Problem 1 (12 points)
a) (6 points) A Quotient Rule error loses 2 points. More minor errors
lose a point.
b) (2 points) 1 point for each answer. Knowing that e0=1 is
worth 1 point in this problem.
c) (2 points) For any correct equation of the line.
d) (2 points) Geometric slope and point are each worth 1 point: the
line should look tangent.
Problem 2 (8 points)
1 point for g(1); 2 points for g´(x) and 1 point for for
g´(1); 3 points for g´´(x) and 1 point for for
g´´(1). 2 points off for an error in the Product Rule or the Chain
Rule.
Problem 3 (10 points)
2 points for correctly instantiating [f(x+h)-f(x)]/h. This is mostly
for substitution of x+h into f (or something equivalent). If this
formula is not quoted correctly, then no credit can be earned in this
problem (it is difficult to compute f´(x) from the definition
when the definition isn't known!). If somehow the student writes
3–x+h instead of 3–(x+h) the student loses these 2 points,
but they can be the only 2 points lost of the 10 if everything else is
correctly done.
3 points for correctly combining the fractions.
2 points for cancelling the h's.
1 point for the answer, which must be the correct answer for the
student's work.
2 points off if there is no mention of limh→0 in an
otherwise correct solution.
The answer alone or the answer obtained algorithmically earns no
credit.
Problem 4 (12 points) Each part is worth 4 points. Simple arithmetic errors lose 1 point each. Errors with the Product Rule or the Quotient Rule lose 2 points each.
Problem 5 (12 points)
The idea of taking the derivative and trying to find x so the
derivative is 0 earns 3 points alone (if this can be read sufficiently
clearly).
The correct derivative is worth 5 points. Solving for an x where
f´(x)=0 earns the remaining 4 points.
Credit can be lost for assuming incorrect algebraic properties of logs
or exponents.
Problem 6 (12 points)
4 points for the hypotenuse in terms of x (2 of these for the "legs"
of the right triangle, and 2 of these for correctly using this
information to get the hypotenuse).
3 points for the correct total length of the horizontal and vertical
sides.
2 points for a correct formula for f(x).
3 points for a correct domain (with or without either or both
endpoints). 1 of these points is earned for a specification of x>0
or x≥0.
Problem 7 (8 points)
The word continuous in relevant context earns 2 points. The
phrase Intermediate Value Theorem in relevant context earns 2
points. This means that just scrawling (scrawl: "write in a
hurried untidy way") the word "continuous" or the phrase "Intermediate
Value Theorem" will not necessarily earn credit. 1 point is earned for
a function value which is positive, and 1 point is earned for a
function value which is negative. Finally, an explicit correct answer
supported by the student's work earns 2 points (an interval of the
form [0,something] in a similar context earns 1 point).
Comment The problem statement contains the following:
You must give evidence supporting your assertion -- the interval given can be any valid interval. The evidence should include specific vocabulary and results from this course.This was interpreted strictly, and answers which themselves referred to fifth roots of numbers were not accepted.
Problem 8 (12 points)
a) (5 points) Factoring the top and bottom is worth 3
points. Cancellation and evaluation earns the remaining 2 points, 1 of
which is for the answer.
b) (2 points) A correct answer earns 1 point. Some support (the word
"continuous" or the phrase "plugging in") earns a second point.
c) (5 points) A correct answer earns 1 point. Some analysis (or even
just acknowledgment!) of absolute value earns 2 points, and then
algebra using this gets 2 more points.
Problem 9 (14 points)
a) (7 points) Restricting attention to 0 and 2 is worth 1 point. 2
points for getting a constraint at 0. 2 points for a similar
constraint at 2. 2 points for solving and reporting correct values of
A and B.
b) (7 points) The graph should be continuous (2 points). 2 points for
the line segments (each correct line segment earns 1 point). 3 points
for an increasing, correctly curved parabolic arc (not curved: 2
points off).
Problem | #1 | #2 | #3 | #4 | #5 | #6 | #7 | #8 | #9 | #10 | #11 | Total |
---|---|---|---|---|---|---|---|---|---|---|---|---|
Max grade | 8 | 10 | 12 | 6 | 8 | 11 | 9 | 11 | 4 | 10 | 10 | 71 | Min grade | 0 | 0 | 0 | 0 | 0 | 0 | 1 | 0 | 0 | 0 | 0 | 14 | Mean grade | 5.82 | 6 | 10 | 2.4 | 3.29 | 4.87 | 4.18 | 6.13 | 3.24 | 3.4 | 2.64 | 51.98 | Median grade | 6 | 6 | 12 | 2 | 2 | 4 | 4 | 6 | 4 | 3 | 2 | 56 |
Numerical grades will be retained for use in computing
the final letter grade in the course.
Here are approximate letter grade assignments for this exam:
Letter equivalent | A | B+ | B | C+ | C | D | F |
---|---|---|---|---|---|---|---|
Range | [85,100] | [80,84] | [70,79] | [65,69] | [55,64] | [50,54] | [0,49] |
Special note
I became convinced after beginning the grading that the work required
for problems 7 and 8 was not equivalent so awarding equal points (10
each) was not appropriate. I changed the point value for problem 7 to
9 points and for problem 8 to 11 points. The following credit reflects
this decision.
Grading guidelines
Minor errors (such as a missing factor in a final answer, sign error,
etc.) will be penalized minimally. Students whose errors materially
simplify the problem will not be eligible for most of the
problem's credit.
The grader will read only what is written and not attempt to guess or
read the mind of the student.
The student should solve the problem given and should not invent
another problem and request credit for working on that problem.
Problem 1 (8 points)
Differentiation of the equation is worth 5 of the 8 points. Each Chain
Rule error loses 2 of these points. 3 points are earned for correctly
solving for y´. Students who simplify the differentiated equation
with a Chain Rule error are eligible for only 2 of the 3 "solving"
points.
Problem 2 (10 points)
a) (5 points) 1 point for the derivative of arctan, 2 points for
correctly using the Chain Rule, and 2 points for correctly using the
Quotient Rule.
b) (5 points) 3 points for the derivative, and 2 points for an
equation of the tangent line (1 point for a correct point and 1 point
for a correct slope). Please note that if the derivative is not
evaluated to get a number, the graph of the resulting equation is not
a line, so it is eligible for only 1 of the 2 equation points.
Problem 3 (12 points)
4 points for a correct equation connecting the distances at a
"general" time, 4 points for correctly differentiating this equation,
and then 4 points for correctly instantiating the equation with
specific information and deducing the desired rate of change.
Problem 4 (6 points)
1 point for correctly selecting a function to use, 1 point for the
derivative, 2 points for the values of the function and the
derivative, and then 2 points for answering the question (correct
assembly of all of the information in something related to the linear
approximation).
Problem 5 (8 points)
Numerical estimates for x1 and x2 will earn 2
points each. The estimates need not be identical to those given in the
instructor's solution, but certainly x1 should be larger
than 2 -- in fact, close to 3, and x2 should be between 2
and x1, and close to 2. Each line segment is worth 2
points. They should be tangent to the curve drawn (starting reasonably
close to 1) and tangent at the correct points.
Problem 6 (10 points)
A statement or use of the idea "Extreme values occur at {endpoints &
critical points}" earns 1 point. Finding the values at the endpoints
earns 2 points. A correct derivative earns 2 points, and finding the
critical point earns 2 points. Finding the value at the critical point
earns 1 point. Finally, 2 points are awarded for the correct answers.
Problem 7 (9 points Please see the note preceding these
remarks.)
The correct derivative earns 2 points. Finding the correct two
critical points earns 2 points. Finding the correct intervals of
{in|de}crease earns 1 point each (some reasoning must be supplied for
each interval) for a total of 3 points. Applying the First Derivative
Test and making the appropriate conclusion for each critical point
earns 1 point each, for a total of 2 points.
Lose 1 point to problem 8.
Problem 8 (11 points Please see the note preceding these
remarks.)
2 points for the first derivative and 3 points for the second
derivative. 3 points for finding the candidates for inflection points
(1 of these is for writing f´´(x)=0). 1 point for each
interval & concavity diagnosis for a total of 3 points.
Problem 9 (4 points)
Each picture earns 2 points, with 1 of the 2 earned for the correct
{in|de}creasing behavior and the other for correct concavity.
Problem 10 (12 points)
Setting up the problem earns 3 points: 1 point for area (constraint)
and 2 points for the cost (objective function). No points will be
earned if perimeter is used instead of cost. Students who consider an
incorrect objective function will still be eligible to earn 8 of the
12 points for this problem if their objective function is as
complicated algebraically as the correct objective function. They
can't get the points for the objective function or for the answer.
Then 3 points for changing to a 1 variable problem and 2 points for
finding the critical value and 2 points for explaining why a minimum
has been found. Some methods different from the supplied answer are
certainly valid: students could analyze the first derivative ("First
Derivative Test") or they could use the second derivative and conclude
that a minimum has been found using concavity.
2 points for the answer (both dimensions are requested!).
Problem 11 (10 points)
Algebraically combining the pieces correctly earns 3 points. The
pieces cannot be analyzed separately! A first use of L'H is worth
3 points: 1 point for considering eligibility, and 2 points for the
differentiation. A second use of L'H is worth 3 points: 1 point for
considering eligibility, and 2 points for the differentiation. The final
answer is worth 1 point.
This is a difficult problem.
The final exam and course grades
Grading the final exam
The final exam was graded by the instructors of Math 151 on Thursday,
December 17 following "rubrics" or grading guides written by the
lecturers. I have a copy of this material. I then sat and reread the
exams and the grades given for about 6 or 7 hours on Saturday,
December 19.
Let's see: there were several arithmetic errors and a number of situations where the grades given seemed to be different from the rubric's suggestions. Almost all of the grading changes I made were +/– 1 or 2 or 3 points, but there were a handful (fewer than 5 changes) which were larger. I'm glad I reread the exams but I don't think that I found and made any changes which were material (that has not been the case with other courses). Here are some statistics about the final exam.
Students | # of students | Grade range | Median grade | Mean grade |
---|---|---|---|---|
All Math 151 (including 153) | 541 | 0 to 200 | 134 | 128.1 |
Math 153 | 44 | 22 to 189 | 129 | 123.6 |
The performance of 153 was, on the whole, somewhat better than might have been predicted statistically for groups of students with similar preparation in other instantiations of Math 151. I think a number of students prepared very diligently for the final exam and these numbers were useful in reporting course grades (more details on that are below). Here are the letter grade assignments for all students who took the exam.
Letter equivalent | A | B+ | B | C+ | C | D | F |
---|---|---|---|---|---|---|---|
Range | [176,200] | [165,175] | [150,164] | [135,149] | [115,134] | [105,114] | [0,104] |
Humans generally behave consistently. Some students lost points because they simplified incorrectly where this was not requested. Some students invented their own problems, and these may not have been related to what was asked. Many students made errors involving high school algebra. I think the final exam was generally straightforward and most students I asked told me that there was enough time to write and check solutions.
Use of these grades
The final exam letter grades are given to allow individual lecturers,
who are responsible for reporting course grades, to align the
performance of their specific groups of students with the overall
performance of students in the course. Random chance may give one
lecturer a group of students with better or worse performance than the
overall population, and, indeed, specific scheduling requirements may
force specific subpopulations with different math preparation to
enroll in some lectures. The common final exam and grading are part of
the faculty's effort to assign appropriate course grades, with equal
grades for equal achievement. In the case of 153, the comparison of
final exam results of the section with the performance of "all
students" certainly helps me to assign grades which reflect student
performance in the "standard" sections.
Course grading
The information I had included the following: grades for the three
exams (two during the semester and the final), textbook homework
scores (reported by the peer mentors), workshop and quiz grades
(reported by Mr. Nakamura), and the number of QotD answered by
students.
I computed a number for each student essentially weighted as previously
described. Attendance was generally very good (thank you!) and I
only thought of penalizing 3 students for poor attendance (their own
efforts effectively penalized them!). Therefore the student numbers
were constructed from the exams, the textbook homework, the number of
QotD answered, the workshop grades and quiz grades, with weights as
described. I then assigned a tentative letter grade based on
breakpoints proportionately derived from the "bins" shown above for
the exams. I examined each student's record to make sure that this
process had not distorted or misrepresented student achievement. I
entered the course grades into the Registrar's computer system on
Monday, December 21. I hope students will be able to see them
soon.
If you have questions ...
Rutgers requests that I retain the final exams. Students may ask to
look at their exams and check the exam grading. These students should
send me e-mail so that a mutually satisfactory meeting time can be
arranged. Students may also ask how their course grades were
determined using the process I described. Probably e-mail will be
sufficient to handle most such inquiries.
Students with grades of D should be
especially concerned about their preparation and likely success in the
second semester (Math 152) of the calculus sequence. Although students
can continue with this grade, experience and statistics suggest that
the chance of future success (passing that course!) is small. If you do
decide to continue, please realize that you will need to allow extra
effort and extra time, and that you'll need to do a great deal of
dull, repetitive practice and serious study.
Maintained by greenfie@math.rutgers.edu and last modified 12/21/2009.