| Problem | #1 | #2 | #3 | #4 | #5 | #6 | #7 | #8 | #9 | Total |
|---|---|---|---|---|---|---|---|---|---|---|
| Max grade | 12 | 8 | 10 | 12 | 12 | 12 | 7 | 10 | 14 | 89 | Min grade | 0 | 0 | 0 | 4 | 0 | 0 | 0 | 0 | 0 | 10 | Mean grade | 9.57 | 4.87 | 4.22 | 9.65 | 4.52 | 7.57 | 1 | 6 | 7.98 | 55.37 | Median grade | 10 | 5 | 3 | 10 | 5 | 0 | 0 | 6 | 10 | 54 |
The two versions of the exam had very similar statistical results.
Numerical grades will be retained for use in computing
the final letter grade in the course.
Here are approximate letter grade assignments for this exam:
| Letter equivalent | A | B+ | B | C+ | C | D | F |
|---|---|---|---|---|---|---|---|
| Range | [85,100] | [80,84] | [70,79] | [65,69] | [55,64] | [50,54] | [0,49] |
Grading guidelines
Minor errors (such as a missing factor in a final answer, sign error,
etc.) will be penalized minimally. Students whose errors materially
simplify the problem will not be eligible for most of the
problem's credit.
The grader will read only what is written and not attempt to guess or
read the mind of the student.
The student should solve the problem given and should not invent
another problem and request credit for working on that problem.
Problem 1 (12 points)
a) (6 points) A Quotient Rule error loses 2 points. More minor errors
lose a point.
b) (2 points) 1 point for each answer. Knowing that e0=1 is
worth 1 point in this problem.
c) (2 points) For any correct equation of the line.
d) (2 points) Geometric slope and point are each worth 1 point: the
line should look tangent.
Problem 2 (8 points)
1 point for g(1); 2 points for g´(x) and 1 point for for
g´(1); 3 points for g´´(x) and 1 point for for
g´´(1). 2 points off for an error in the Product Rule or the Chain
Rule.
Problem 3 (10 points)
2 points for correctly instantiating [f(x+h)-f(x)]/h. This is mostly
for substitution of x+h into f (or something equivalent). If this
formula is not quoted correctly, then no credit can be earned in this
problem (it is difficult to compute f´(x) from the definition
when the definition isn't known!). If somehow the student writes
3–x+h instead of 3–(x+h) the student loses these 2 points,
but they can be the only 2 points lost of the 10 if everything else is
correctly done.
3 points for correctly combining the fractions.
2 points for cancelling the h's.
1 point for the answer, which must be the correct answer for the
student's work.
2 points off if there is no mention of limh→0 in an
otherwise correct solution.
The answer alone or the answer obtained algorithmically earns no
credit.
Problem 4 (12 points) Each part is worth 4 points. Simple arithmetic errors lose 1 point each. Errors with the Product Rule or the Quotient Rule lose 2 points each.
Problem 5 (12 points)
The idea of taking the derivative and trying to find x so the
derivative is 0 earns 3 points alone (if this can be read sufficiently
clearly).
The correct derivative is worth 5 points. Solving for an x where
f´(x)=0 earns the remaining 4 points.
Credit can be lost for assuming incorrect algebraic properties of logs
or exponents.
Problem 6 (12 points)
4 points for the hypotenuse in terms of x (2 of these for the "legs"
of the right triangle, and 2 of these for correctly using this
information to get the hypotenuse).
3 points for the correct total length of the horizontal and vertical
sides.
2 points for a correct formula for f(x).
3 points for a correct domain (with or without either or both
endpoints). 1 of these points is earned for a specification of x>0
or x≥0.
Problem 7 (8 points)
The word continuous in relevant context earns 2 points. The
phrase Intermediate Value Theorem in relevant context earns 2
points. This means that just scrawling (scrawl: "write in a
hurried untidy way") the word "continuous" or the phrase "Intermediate
Value Theorem" will not necessarily earn credit. 1 point is earned for
a function value which is positive, and 1 point is earned for a
function value which is negative. Finally, an explicit correct answer
supported by the student's work earns 2 points (an interval of the
form [0,something] in a similar context earns 1 point).
Comment The problem statement contains the following:
You must give evidence supporting your assertion -- the interval given can be any valid interval. The evidence should include specific vocabulary and results from this course.This was interpreted strictly, and answers which themselves referred to fifth roots of numbers were not accepted.
Problem 8 (12 points)
a) (5 points) Factoring the top and bottom is worth 3
points. Cancellation and evaluation earns the remaining 2 points, 1 of
which is for the answer.
b) (2 points) A correct answer earns 1 point. Some support (the word
"continuous" or the phrase "plugging in") earns a second point.
c) (5 points) A correct answer earns 1 point. Some analysis (or even
just acknowledgment!) of absolute value earns 2 points, and then
algebra using this gets 2 more points.
Problem 9 (14 points)
a) (7 points) Restricting attention to 0 and 2 is worth 1 point. 2
points for getting a constraint at 0. 2 points for a similar
constraint at 2. 2 points for solving and reporting correct values of
A and B.
b) (7 points) The graph should be continuous (2 points). 2 points for
the line segments (each correct line segment earns 1 point). 3 points
for an increasing, correctly curved parabolic arc (not curved: 2
points off).
Maintained by greenfie@math.rutgers.edu and last modified 10/9/2009.