From: Richard Stanley rstan at math dot mit dot edu To: ayyer at physics.rutgers.edu, zeilberg at math.rutgers.edu Subject: Razumov-Stroganov Dear Professor Ayyer and Doron, In your interesting approach toward the Razumov-Stroganov conjecture you state that "To the best of our knowledge, this is the first time the Razumov-Stroganov conjecture has been interpreted in this way." I actually did something similar in a posting to the domino mailing list in 2001 (appended below). At this time it seems that the complete description of the eigenvector had not yet been conjectured. Best regards, Richard ************************************************************ Date: Sat, 24 Feb 2001 16:57:06 -0500 (EST) From: Richard StanleyTo: propp@math.wisc.edu CC: domino@math.wisc.edu Subject: Re: the XXZ and 6V models Jim asked: > Can any of you explain what the XXZ model is about? Here is a restatement of the main conjecture of Razumov and Stroganov in "familiar" terms: Let n be a positive integer and N=2n+1. Let B be the set of binary N-tuples u=(u_1,...,u_N) with n 1's, so #B = {N\choose n}. Regard u as a circular sequence, so u_{N+1}=u_1. Define a real matrix P whose rows and columns are indexed by B, as follows. P(u,u) = (N - 2a(u))/2, where a(u) is the number of entries u_i of u such that u_i = u_{i+1}. If u \neq v, then P(u,v)=2 if u and v differ by an adjacent transposition. Otherwise P(u,v)=0. It is a theorem that P has an eigenvalue -3N/2. Let \psi be the corresponding eigenvector. CONJECTURE. \psi may be chosen so that all entries are positive. (Razumov-Stroganov state that this is a consequence of the Perron-Frobenius theorem, though I don't immediately see this.) Normalize \psi so that its least component is 1. Then its largest component is A_n, the number of nxn alternating sign matrices. NOTE. It's easy to see that \psi_u (the component of \psi indexed by u) depends only on the cyclic equivalence class (necklace) of u. EXAMPLE. n=2. Order the elements of B as 11000,01100,00110,00011,10001,10100,01010,00101,10010,01001, The matrix P has the block form [X Y] [Z W] where each block is 5x5. X is the diagonal matrix with -1/2 on the diagonal. Y is the circulant matrix with first row (2,0,0,0,2). Z is the circulant matrix with first row (2,2,0,0,0). W is the circulant matrix with first row (3/2,0,2,2,0). -15/2 is an eigenvalue, with eigenvector \psi = (1,1,1,1,1,2,2,2,2,2). Richard